Maan lijiye humein ek Quadratic Equation (do-darji musawat) solve karni hai:
### Sawal:
x^2 - 5x + 6 = 0 mein x ki value maloom karein.
### Hal (Solution):
Is sawal ko hum Factorization (ajza-e-zarbi) ke zariye solve karenge. Humein do aise numbers chahiye jinhein multiply karne par +6 aaye aur jama (add) karne par -5 aaye.
Woh numbers -2 aur -3 hain.
Step 1: Middle term ko split karna
Step 2: Common nikalna
Pehli do terms se x common lein aur baaki do se -3:
Step 3: Factors banana
Ab (x - 2) ko common le lein:
Step 4: x ki values nikalna
Ab ya to (x - 2) = 0 hoga ya (x - 3) = 0:
1. Agar x - 2 = 0, to x = 2
2. Agar x - 3 = 0, to x = 3
Jawab: x ki do values hain: 2 aur 3.
Upar diye gaye graph mein aap dekh sakte hain ke jab ek quadratic equation ko graph par dikhaya jata hai, to woh x-axis ko un points par kaat-ta hai jo uske solutions (roots) hote hain.
Aapke paas koi khaas sawal hai? Algebra, Geometry, Calculus ya Trigonometryโaap apna sawal yahan likhein, main use solve kar doonga!
April 26, 2026 119
