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Less code, less bug — Aziziy Dev | Dangasa — TG.ME

Aziziy Dev | Dangasa@aziziy_dev · 83 subscribers Open in TelegramOpen

Less code, less bug

t.me/aziziy_dev/1594

September 2, 2026 29 2

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Kim nima desa desin coding + musicni vibe boshqacha 33·Aug 31 Dangasalik yo'qolyaptimi-a? 118·Aug 21

Shallow Copy & Deep Copy Tassavur qilaylik bizda bitta a o'zgaruvchisi bor: let a = 5; Va biz uni keyinchalik boshqa o'zgaruvchiga tengladik: let b = a console.log(a, b) // Natija: 5,5 Bunday holatda albatta natija 5 va 5 chiqadi buni bilamiz. Keyinchalik misol uchun b = 7 natijani chiqarsak albatta 5 va 7 javob olamiz. Bu yerda hech qanday WOW deydigan joy yo'q. Endi keling buni primitiv ma'lumot turida emas reference ma'lumot turadi ko'ramiz misol uchun object. Deylik bizda shunday object bor: const person = { name: "Azizbek", age: 20 } Uni ham keling boshqa o'zgaruvchiga tenglaymiz va qiymatini o'zgartirib ko'ramiz: const newPerson = person; newPerson.name = "Otabek" newPerson.age = 16 console.log(person, newPerson) Bunaqa holatda biz shunday natija konsolda shunday natija olamiz: { name: 'Otabek', age: 16 } { name: 'Otabek', age: 16 } E'tibor bergan bo'lsangiz bu holatda primitiv turdan farqli ravishda person obj'sini qiymatlari ham o'zgarib qoldi. Nimaga deyilsa, javob oddiy biz shallow copy ya'ni sayoz nusxalash qilyapmiz. Buni oldini olish mumkinmi? Ha oldini olish mumkin buning uchun biz deep ya'ni chuqur nusxalashdan foydalanishimiz kerak: const newPerson = {...person}; newPerson.name = "Otabek" newPerson.age = 16 console.log(person, newPerson) // Natija: { name: 'Azizbek', age: 20 } { name: 'Otabek', age: 16 } Ko'rib turganingizdek bu holatda biz newPerson'ni shunchaki person'ga tenglab qo'ymayapmiz, balki person objsini ... (spread operatori) orqali qaytadan yoyyapmiz. Bu uslubimizni agarda arrayga qo'llamoqchi bo'lsangiz shunchaki {} qavslar o'rniga [] qavslardan foydalanamiz. Misol: const newPerson = [...person]; @azizify 117·Aug 21 Changib ketayapti kanal aktiv ko'rsatib beringlar bir)) 85·Aug 18

Javascript Destructuring Tassavur qilaylik bizda shunday array bor: const mevalar = ["olma", "behi", "nok", "gilos"]; Agarda shu to'rtta elementni siklsiz har birini consolega chiqarmoqchi bo'lsak shunday usuldan foydalanar edik: const olma = mevalar[0]; const behi = mevalar[1]; const nok = mevalar[2]; const gilos = mevalar[3]; console.log(olma, behi, nok, gilos) Ko'rib turganingizdek bu kodlarni ko'paytirishga sababchi bo'lmoqda. Buni esa biz Js Destructuring osonroq qilishimiz mumkin. Destructuring bilan: const [apple, behi, nok, cherry] = ["olma", "behi", "nok", "gilos"]; console.log(apple, behi, nok, cherry) Ushbu holatda biz array nomi o'rniga [] qavslar ichiga har bir element uchun ixtiyoriy nom kiritishimiz kerak. Manga faqat boshidagi ikkita elementni o'zi yetadi qolganlari array bo'lib qaytaversin deysizmi? Uni ham yechimi bor: const [apple, behi, ...boshqaMevalar] = ["olma", "behi", "nok", "gilos"]; console.log(apple, behi, boshqaMevalar) Ushbu holatda biz ... (rest operatori)dan foydalanishimiz kerak. boshqaMevalar listida esa bizga qolgan elementlarni arrayi qaytadi. Buni albatta faqat array bilan emas object bilan ham qilsa bo'ladi. Tassavur qilaylik bizda shunday object bor: const person = { name: "Azizbek", age: 20, job: "Developer" } Buni destructuring qilish uchun esa shunday tarzda yozamiz: const {name, age, job} = { // ... } console.log(name, age, job) Bu holatda esa biz obj nomi o'rniga endi {} qavslardan foydalanishimiz kerak va har bir element uchun mos kalit so'zni kiritishimiz kerak. Objectni destructuring qilishda asosiy yoddan chiqarmaslik kerak bo'lgan narsa bu biz kiritgan nom obj elementini key nomi bilan bir xil bo'lishi shart! Agarda sizga to'liq destructing qilish kerak bo'lmasa: const {name, ...etcData} = { // ... } Bunday holatda ham shunchaki rest operatoridan foydalamiz. Ammo siz o'jarlik qilib yo'q men key nomi bilan bir xil nom qilishni xohlamayman desangiz unda shunchaki shu usuldan foydalaning: const {name: ism, ...etcData} = { name: "Azizbek", age: 20, job: "Developer" } console.log(ism, etcData) Buni shunchaki shu usuldan bilan qilsangiz bo'ladi) @azizify 83·Aug 18

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